%% bare_jrnl_compsoc.tex
%% V1.3
%% 2007/01/11
%% by Michael Shell
%% See:
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%%
%% This is a skeleton file demonstrating the use of IEEEtran.cls
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\usepackage{graphicx}
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\usepackage{amsfonts,amsmath,amssymb}
\providecommand\citet{\cite}
\providecommand\citep{\cite}
\providecommand\citealt{\cite}
\usepackage{url}
\usepackage{hyperref}
\hypersetup{colorlinks=false,pdfborder={0 0 0}}
\usepackage{etoolbox}
\makeatletter
\patchcmd\@combinedblfloats{\box\@outputbox}{\unvbox\@outputbox}{}{%
\errmessage{\noexpand\@combinedblfloats could not be patched}%
}%
\makeatother
% You can conditionalize code for latexml or normal latex using this.
\newif\iflatexml\latexmlfalse
\providecommand{\tightlist}{\setlength{\itemsep}{0pt}\setlength{\parskip}{0pt}}%
\AtBeginDocument{\DeclareGraphicsExtensions{.pdf,.PDF,.eps,.EPS,.png,.PNG,.tif,.TIF,.jpg,.JPG,.jpeg,.JPEG}}
\usepackage[utf8]{inputenc}
\usepackage[ngerman,romanian,english]{babel}
% *** CITATION PACKAGES ***
%
\ifCLASSOPTIONcompsoc
% IEEE Computer Society needs nocompress option
% requires cite.sty v4.0 or later (November 2003)
\usepackage[nocompress]{cite}
\else
% normal IEEE
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\fi
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% and later. Note also the use of a CLASSOPTION conditional provided by
% IEEEtran.cls V1.7 and later.
% *** MATH PACKAGES ***
%
%\usepackage[cmex10]{amsmath}
% A popular package from the American Mathematical Society that provides
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%
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%\usepackage{algorithmic}
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%\usepackage{array}
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% Also highly recommended is Mark Wooding's extremely powerful MDW tools,
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% http://www.ctan.org/tex-archive/macros/latex/contrib/eqparbox/
% *** SUBFIGURE PACKAGES ***
%\ifCLASSOPTIONcompsoc
%\usepackage[tight,normalsize,sf,SF]{subfigure}
%\else
%\usepackage[tight,footnotesize]{subfigure}
%\fi
% subfigure.sty was written by Steven Douglas Cochran. This package makes it
% easy to put subfigures in your figures. e.g., "Figure 1a and 1b". For IEEE
% work, it is a good idea to load it with the tight package option to reduce
% the amount of white space around the subfigures. Computer Society papers
% use a larger font and \sffamily font for their captions, hence the
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% installed on most LaTeX systems. The latest version and documentation can
% be obtained at:
% http://www.ctan.org/tex-archive/obsolete/macros/latex/contrib/subfigure/
% subfigure.sty has been superceeded by subfig.sty.
%\ifCLASSOPTIONcompsoc
% \usepackage[caption=false]{caption}
% \usepackage[font=normalsize,labelfont=sf,textfont=sf]{subfig}
%\else
% \usepackage[caption=false]{caption}
% \usepackage[font=footnotesize]{subfig}
%\fi
% subfig.sty, also written by Steven Douglas Cochran, is the modern
% replacement for subfigure.sty. However, subfig.sty requires and
% automatically loads Axel Sommerfeldt's caption.sty which will override
% IEEEtran.cls handling of captions and this will result in nonIEEE style
% figure/table captions. To prevent this problem, be sure and preload
% caption.sty with its "caption=false" package option. This is will preserve
% IEEEtran.cls handing of captions. Version 1.3 (2005/06/28) and later
% (recommended due to many improvements over 1.2) of subfig.sty supports
% the caption=false option directly:
%\ifCLASSOPTIONcompsoc
% \usepackage[caption=false,font=normalsize,labelfont=sf,textfont=sf]{subfig}
%\else
% \usepackage[caption=false,font=footnotesize]{subfig}
%\fi
%
% The latest version and documentation can be obtained at:
% http://www.ctan.org/tex-archive/macros/latex/contrib/subfig/
% The latest version and documentation of caption.sty can be obtained at:
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% *** FLOAT PACKAGES ***
%
%\usepackage{fixltx2e}
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% Frank Mittelbach and David Carlisle. This package corrects a few problems
% in the LaTeX2e kernel, the most notable of which is that in current
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%\usepackage{stfloats}
% stfloats.sty was written by Sigitas Tolusis. This package gives LaTeX2e
% the ability to do double column floats at the bottom of the page as well
% as the top. (e.g., "\begin{figure*}[!b]" is not normally possible in
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% that authors should try to avoid such use. Do not be tempted to use the
% cuted.sty or midfloat.sty packages (also by Sigitas Tolusis) as IEEE does
% not format its papers in such ways.
%\ifCLASSOPTIONcaptionsoff
% \usepackage[nomarkers]{endfloat}
% \let\MYoriglatexcaption\caption
% \renewcommand{\caption}[2][\relax]{\MYoriglatexcaption[#2]{#2}}
%\fi
% endfloat.sty was written by James Darrell McCauley and Jeff Goldberg.
% This package may be useful when used in conjunction with IEEEtran.cls'
% captionsoff option. Some IEEE journals/societies require that submissions
% have lists of figures/tables at the end of the paper and that
% figures/tables without any captions are placed on a page by themselves at
% the end of the document. If needed, the draftcls IEEEtran class option or
% \CLASSINPUTbaselinestretch interface can be used to increase the line
% spacing as well. Be sure and use the nomarkers option of endfloat to
% prevent endfloat from "marking" where the figures would have been placed
% in the text. The two hack lines of code above are a slight modification of
% that suggested by in the endfloat docs (section 8.3.1) to ensure that
% the full captions always appear in the list of figures/tables - even if
% the user used the short optional argument of \caption[]{}.
% IEEE papers do not typically make use of \caption[]'s optional argument,
% so this should not be an issue. A similar trick can be used to disable
% captions of packages such as subfig.sty that lack options to turn off
% the subcaptions:
% For subfig.sty:
% \let\MYorigsubfloat\subfloat
% \renewcommand{\subfloat}[2][\relax]{\MYorigsubfloat[]{#2}}
% For subfigure.sty:
% \let\MYorigsubfigure\subfigure
% \renewcommand{\subfigure}[2][\relax]{\MYorigsubfigure[]{#2}}
% However, the above trick will not work if both optional arguments of
% the \subfloat/subfig command are used. Furthermore, there needs to be a
% description of each subfigure *somewhere* and endfloat does not add
% subfigure captions to its list of figures. Thus, the best approach is to
% avoid the use of subfigure captions (many IEEE journals avoid them anyway)
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% *** PDF, URL AND HYPERLINK PACKAGES ***
%
%\usepackage{url}
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% \url{my\_url\_here}.
% *** Do not adjust lengths that control margins, column widths, etc. ***
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% There should be no need to do such things with IEEEtran.cls V1.6 and later.
% (Unless specifically asked to do so by the journal or conference you plan
% to submit to, of course. )
% correct bad hyphenation here
\hyphenation{op-tical net-works semi-conduc-tor}
\begin{document}
%
% paper title
% can use linebreaks \\ within to get better formatting as desired
\title{Excersise solution theme 4}
%
%
% author names and IEEE memberships
% note positions of commas and nonbreaking spaces ( ~ ) LaTeX will not break
% a structure at a ~ so this keeps an author's name from being broken across
% two lines.
% use \thanks{} to gain access to the first footnote area
% a separate \thanks must be used for each paragraph as LaTeX2e's \thanks
% was not built to handle multiple paragraphs
%
%
%\IEEEcompsocitemizethanks is a special \thanks that produces the bulleted
% lists the Computer Society journals use for "first footnote" author
% affiliations. Use \IEEEcompsocthanksitem which works much like \item
% for each affiliation group. When not in compsoc mode,
% \IEEEcompsocitemizethanks becomes like \thanks and
% \IEEEcompsocthanksitem becomes a line break with idention. This
% facilitates dual compilation, although admittedly the differences in the
% desired content of \author between the different types of papers makes a
% one-size-fits-all approach a daunting prospect. For instance, compsoc
% journal papers have the author affiliations above the "Manuscript
% received ..." text while in non-compsoc journals this is reversed. Sigh.
\author{Joset Geovanni Pacheco Castillo% <-this % stops a space
\IEEEcompsocitemizethanks{\IEEEcompsocthanksitem Joset Geovanni Pacheco Castillo is with Instituto Tecnológico Superior Zacatecas Occidente\protect\\
% note need leading \protect in front of \\ to get a newline within \thanks as
% \\ is fragile and will error, could use \hfil\break instead.
\IEEEcompsocthanksitem }}% <-this % stops a space
%\thanks{Manuscript received \today;}
% note the % following the last \IEEEmembership and also \thanks -
% these prevent an unwanted space from occurring between the last author name
% and the end of the author line. i.e., if you had this:
%
% \author{....lastname \thanks{...} \thanks{...} }
% ^------------^------------^----Do not want these spaces!
%
% a space would be appended to the last name and could cause every name on that
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% "AB" then you have to do: "\textbf{A}\textbf{B}"
% \thanks is no different in this regard, so shield the last } of each \thanks
% that ends a line with a % and do not let a space in before the next \thanks.
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% you are supposed to have spaces between the names. For what it is worth,
% this is a minor point as most people would not even notice if the said evil
% space somehow managed to creep in.
% The paper headers
\markboth{Computer Science Journal of IEEE,~Vol.~1, No.~1, 2013}%
{Joset Geovanni Pacheco Castillo : Excersise solution theme 4}
% The only time the second header will appear is for the odd numbered pages
% after the title page when using the twoside option.
%
% *** Note that you probably will NOT want to include the author's ***
% *** name in the headers of peer review papers. ***
% You can use \ifCLASSOPTIONpeerreview for conditional compilation here if
% you desire.
% The publisher's ID mark at the bottom of the page is less important with
% Computer Society journal papers as those publications place the marks
% outside of the main text columns and, therefore, unlike regular IEEE
% journals, the available text space is not reduced by their presence.
% If you want to put a publisher's ID mark on the page you can do it like
% this:
%\IEEEpubid{0000--0000/00\$00.00~\copyright~2007 IEEE}
% or like this to get the Computer Society new two part style.
%\IEEEpubid{\makebox[\columnwidth]{\hfill 0000--0000/00/\$00.00~\copyright~2007 IEEE}%
%\hspace{\columnsep}\makebox[\columnwidth]{Published by the IEEE Computer Society\hfill}}
% Remember, if you use this you must call \IEEEpubidadjcol in the second
% column for its text to clear the IEEEpubid mark (Computer Society jorunal
% papers don't need this extra clearance.)
% use for special paper notices
%\IEEEspecialpapernotice{(Invited Paper)}
% for Computer Society papers, we must declare the abstract and index terms
% PRIOR to the title within the \IEEEcompsoctitleabstractindextext IEEEtran
% command as these need to go into the title area created by \maketitle.
\IEEEcompsoctitleabstractindextext{%
% IEEEtran.cls defaults to using nonbold math in the Abstract.
% This preserves the distinction between vectors and scalars. However,
% if the journal you are submitting to favors bold math in the abstract,
% then you can use LaTeX's standard command \boldmath at the very start
% of the abstract to achieve this. Many IEEE journals frown on math
% in the abstract anyway. In particular, the Computer Society does
% not want either math or citations to appear in the abstract.
% Note that keywords are not normally used for peerreview papers.
%\begin{IEEEkeywords}
%Computer Society, IEEEtran, journal, \LaTeX, paper, template.
%\end{IEEEkeywords}
}
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% papers do!
\IEEEdisplaynotcompsoctitleabstractindextext
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% compsoc under a non-conference mode.
% For peer review papers, you can put extra information on the cover
% page as needed:
% \ifCLASSOPTIONpeerreview
% \begin{center} \bfseries EDICS Category: 3-BBND \end{center}
% \fi
%
% For peerreview papers, this IEEEtran command inserts a page break and
% creates the second title. It will be ignored for other modes.
\IEEEpeerreviewmaketitle
\subsection*{Introduction.}
{\label{551055}}
This document will show exercises performed with the knowledge that was
acquired during the course of the unit four.
1. -
A) The ambient temperature is usually taken as 68 \selectlanguage{ngerman}° F. How much is this
in Celsius?
To achieve the conversion, the following formula must be taken into
account:
\par\null
\begin{equation}
\(T\left(C\right)=\frac{5}{9}\left[F-32\right]\)
\end{equation}
Once we know, we proceed to replace:
\par\null
\begin{equation}
\(T\left(C\right)=\frac{5}{9}\left[68-32\right]=20\)
\end{equation}
Then you have the result is~ ~ ~ 20 ° C.
B) The temperature of the filament of a spotlight is 1900 ° C. How much
is in Fahrenheit?
Using the same formula as in the previous section only, with a small
change:
\par\null
\begin{equation}
\(T\left(F\right)=\frac{9}{5}\left[C-32\right]\)
\end{equation}
Once we know, we proceed to replace:
\par\null
\begin{equation}
\(T\left(F\right)=\frac{9}{5}\left[1900-32\right]=3477.6\)
\end{equation}
Once the operation was performed, we already have the result 3477.6;
which can be rounded to 3478 ° F.
\par\null
2. -In an alcohol thermometer, the alcohol column has a length of
11.82cm at 0 ° centigrade, and a length of 21.85cm at 100 ° centigrade.
What is the temperature if the column has:
A) A length of 18.70cm.
B) A length of 14.60cm.
To solve this problem, it is necessary to transform into an equation;
therefore, give each data of the problem a value. In order to achieve
this, it is necessary to base ourselves on the following formula:
To solve this problem, it is necessary to transform into an equation;
therefore, give each data of the problem a value. In order to achieve
this, it is necessary to base ourselves on the following formula:
\begin{equation}
\(y=mx+b\)
\end{equation}
Now that you have the formula, you proceed to clear each of its
components in order to apply it. Starting at m:
\par\null
\begin{equation}
\(m=\frac{y2-y1}{x2-x1}\)
\end{equation}
Now that you have the formula for calculating m, each value will be
given an identity:
\par\null
\begin{equation}
\(\left(x1,\ y1\right),\ \left(x2,\ y2\right)=\left(11.82,\ 0\right),\ \left(21.85,\ 100\right)\)
\end{equation}
Now we can apply the formula:
\par\null
\begin{equation}
\(m=\frac{100-0}{21.85-11.82}=\frac{100}{10.03}=9.97\)
\end{equation}
Now that we know m, we will clear b:
\par\null
\begin{equation}
\(o=\left(9.97\right)\left(11.82\right)+b\)
\end{equation}
\begin{equation}
\(b=-\left(9.97\right)\left(11.82\right)=-117.84\)
\end{equation}
Now we only need to know x, but in this equation we know that x is the
value that must be entered as length to know the temperature. So we have
to substitute x for the value of subsection A:~
\par\null
\begin{equation}
\(y=\left(9.97\right)\left(x\right)+\left(-117.84\right)\)
\end{equation}
\begin{equation}
\(y=\left(9.97\right)\left(18.70\right)-117.84=68.59\)
\end{equation}
Then we have that when x is 18.70 the temperature is 68.59 ° C.
Now we substitute x for the value of subsection B.
\par\null
\begin{equation}
\(y=\left(9.97\right)\left(14.6\right)-117.84=27.71\)
\end{equation}
Then we have that when x is 14.60 the temperature is 27.71° C. ~
\par\null
3. -An average active person consumes around 2500Kcal a day.
A)How much is this in Joule?
B)How much is this in Kilowatts / hour?
C)If CFE charges you 10c per kilowatt / hour. How much will the energy
cost for a day if you buy it from CFE? Could you feed yourself this
amount of money per day?
To solve subsection A you must know how much is 1Kcal. So when
investigating it gives us that:
\par\null
\begin{equation}
\(1Kcal=4.186x10^3J/Kcal\)
\end{equation}
So knowing this multiply the kilocalories by
4.186x10\textsuperscript{3}.
\par\null
\begin{equation}
\(\left(2500Kcal\right)\left(4186x10^3J/Kcal\right)=1.046x10^7J\)
\end{equation}
A)Then give us result for this paragraph: 1.046x10\textsuperscript{7}J.
Now we continue to solve the subsection B, for this we must know the
formula to calculate Watt:
\par\null
\begin{equation}
\(Watt=\frac{J}{S}\)
\end{equation}
Once we know the formula, it only remains to substitute to arrive at the
answer:
\par\null
\begin{equation}
\(Watt=\frac{1.046x10^7}{3600}=2.9x10^3w/h=2.9Kw/h\)
\end{equation}
B) Then give us result for this paragraph: 2.9Kw/h.
Now that we know the amount of Watt / Hour we can calculate how much to
pay CFE per hour, for 24 Hours and determine if one can survive or not
one day alone with that money. All this will be done in a single
operation shown below:
\par\null
\begin{equation}
\(\left(2.9Kw/h\right)\left(10c\right)=\left(29c/h\right)\left(24h\right)=697.44c\)
\end{equation}
C) Now that we know that CFE paid 697.44c or 6.97d for one day, we
deduce that it is impossible to survive all day with your 3 meals with
only 6.97d (unless you only eat 1 dollar pizza at each meal, which is
not healthy but you would not be hungry).
\par\null
4. -How many Joule and Kcal are generated when you apply the brakes to
stop a 1200Kg car that comes at 95K / h?~
In order to solve this problem we must take into account the following
formula:
\par\null
\begin{equation}
\(\selectlanguage{romanian}ɅK=Kf-Ki\)
\end{equation}
Now, looking at the formula we notice that we already have Kf which is 0
since the car will stop, but we still lack Ki, so to calculate Ki we use
the following formula:~
\par\null
\begin{equation}
\(Ki=\frac{1}{2}mu^2\)
\end{equation}
Now we substitute in the first formula:
\par\null
\begin{equation}
\(K=0-\frac{1}{2}\left(1200Kg\right)\left(95K/h\right)\)
\end{equation}
To continue, the Km / h in m / s will be transformed:
\par\null
\begin{equation}
\(95Km/h=95000m/h\left(\frac{1h}{3600s}\right)=26.4m/s\)
\end{equation}
Now we will put it in the operation:
\par\null
\begin{equation}
\(K=0-\left(600Kg\right)\left(26.4m/s\right)2=-418176J\)
\end{equation}
Then we know that the answer in Joule is -418176J, now we only transform
it to KJ in order to calculate the Kcal:
\par\null
\begin{equation}
\(\left(-418176J\right)\left(1000\right)=-418.176KJ\)
\end{equation}
It only remains to transform it to Kcal:
\par\null
\begin{equation}
\(\left(-418.176KJ\right)\cdot\left(\frac{1Kcal}{4.186KJ}\right)=-99.9Kcal\)
\end{equation}
5. - The cooling system of a car has 18 liters of water. How much heat
do you absorb if your temperature rises from 15 \selectlanguage{ngerman}° to 95 ° C?
In order to solve this problem, the following formula is necessary:
\par\null
\begin{equation}
\(Q=mc\selectlanguage{romanian}ɅT\)
\end{equation}
Now that we know the formula it is necessary to calculate each of its
elements, starting with the m:
\par\null
\begin{equation}
\(m=pv=\left(1Kg/Lt\right)\left(18Lt\right)=18Kg\)
\end{equation}
We already have m, now we calculate c:
\par\null
\begin{equation}
\(c=4186J/Kg\ C\)
\end{equation}
Finally, we calculate ɅT:
\par\null
\begin{equation}
\(ɅT=95-15=80\)
\end{equation}
Once we have all the components, we substitute them in the formula and
do the calculation:
\par\null
\begin{equation}
\(Q=\left(18Kg\right)\left(4186J/Kg\ C\right)\left(80\right)=6.0x10^6J\)
\end{equation}
So we arrive at the final result which is 6.0x10\textsuperscript{6}J.
\subsection*{Conclusion.}
{\label{556748}}
To conclude with this practice, it is important to emphasize how
educational and fun it was to perform the problems in class with the
rest of the group. While it is true that this time there was no friendly
competition between peers, even so the information retained by the
student was greater than just listen and try to solve problems alone.
\selectlanguage{english}
\FloatBarrier
\end{document}